This question was uploaded on 04/11/21 on social media accounts.
Solution:
\[x = \frac{R+r}2\]
\[y = \frac{R-r}2\]
\[a=b=\sqrt{x^2-y^2}=\sqrt{rR}\]
\[\Rightarrow a+b=2\sqrt{rR}\]
Dare2solve | Common tangent to circle and semicircles - Circle passes through center of semicircles
in
Circle
Geometry
Length
published on November 05, 2021
