This question was uploaded on 25/01/22 on social media accounts.
Solution:
Given that, a:b = 3:4
Let AB = 15 and BC = 20 so AC = 25, AE = 9, CE = 16
2x + 2y = 90 (or) x + y = 45
<BDC = 90 - x = x + 2y
<BFA = 90 - y = 2x + y
By this, Triangles ABF and CBD are isosceles.
So, AF = 15 and CD = 20
Also, AD = 5 and FC = 10
Now, DE = AE - AD = 9 - 5 = 4
and, FE = CE - CF = 16 - 10 = 6
c:d = DE:FE = 4:6 = 2:3
